To help with CSDF, picking up three colour quantum numbers: STC array of colour quantum numbers of flavour quarks.ĭue to baryons all are “white colour” particles, which are made of colourful quarks. FlavourĪnd colour q RGB are the identities of quark particles.ĭefinition CSDF, Colour Spectrum Diagram of Flavour is composed of six (or more) colour spectral line arrays of flavour quarks, somewhat similar to the Gene diagram of chromosomes. Is colour spectral line array of flavour d quark. Is the colour spectral line array of flavour u quark, and array In STS ( Table 2), quark could even possess colour quantum number array that called as Colour Spectral Line Array labelled by q RGB (20), which is an array comprised of three colour quantum numbers, marked q R, q G and q B, they are third-fractions.ĭifferent flavour quark possesses its own colour spectral line array, for example, array Now Suppose that except flavour quantum number marked Is named as flavour quantum number of quarks, which are even numbers. Flavour quantum number of quarks in STS (isospin Now we continue Table 1 quark model in STS, in flavour isotopic space, , STC, Spin Topological Coordinate of spin particle in STS.Īre Casimir operator and the third component of spin particle If in case of no confusion, it is convenient to instead of (5) to use (9) to deal with
Is the vacuum background spin angular momentum of , we get the expressions for the eigenvalue of Casimir OperatorĪnd the eigenvalue of the third componentĪre diagonal infinite dimensional matrices. Is an infinite dimensional Hermitian Matrix.
Satisfy angular momentum commutation rule (2)Īre two infinite dimensional Non-Hermitian Matrices. Of a spin particle in STS math frame, is labelled by two subscripts Of isospin 1/2 particles, that labelled by mark ♦, which are greater than +1/2 or less than −1/2 in Table 1? Next, we resort to Spin Topological Space ( ), abbreviation STS, that can help us to construct what we want to get the right side in Table 1. In Table 1, the right side is more graceful and elegant than the left side, but how can we obtain those third component eigenvalues Following the unified math symmetry picture, all eigenvalues of Of six flavour quarks should not be the same each other. According to Pauli Exclusion Principle, PEP, each of those values of It is a curious question, what will happen? if the above six flavour quarks are all put into a common multiplet, that is, if these flavours are treated equally in one isotopic spin space. Further, there is an isodoublet and there are four isosinglets in isospin scheme for flavour quarks. And the remaining four flavour quarksĪre assigned to four isosinglets with I = 0, respectively, the dimension of matrix representation of each isosinglet is equal to This matrix representation is an analogy with ordinary angular momentum , the dimension of matrix representation of the isodoublet is equal to ) quarks are assigned to an isodoublet with
In isotopic spin space of Standard Model, SM, Gell-Mann M and Zweig G, the isospin quantum number I and the third component I 3, for flavour quarks u, d are 1/2, +1/2 and 1/2, −1/2 respectively, for flavour quarks
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